Just recorded a quick
It's almost impossible for me to leave comments ... but You are a genius. Thanks a Million....
I see how this would work with Class C. How would you come up with the usuable IP's for Class A & B?
As you said you are working with a / 11, how did you know that it would be 2nd oxted? Also would this chart work with classes A and B? Thanks
@3:30 How did you get 9, 10, 11? I don’t quite get that part.
Best video for Subnetting. Basic and Simple.
This video lecture is
didnt understand only..!!
stop fumbling and repeating OKs,jst concentrate on how well u can explain..Your explanation is not at all upto the mark bcaz its confusing,i'm sry to say that but it's true..
sir i hardly trying to understand this pls in 9:20 what the connection between 52 and 12?
asshole
For the people that are confused starting at 5:18:
At this point he is explaining that with a block size of 2^8 the only bits that could possibly not be divisible by 2^8 are the last 8 bits (bits 7-0). What he is doing with a31*2^31+a30*2^30 business is representing the ip address as a binary integer instead of a dotted decimal. For instance a31 represents the left most (most significant) bit in the address. all of the a31...a0 are just bits (0 or 1)
In the example that follows, where we are checking a block that contains 16 addresses the only bits that can't be divisible by 16 are the last 4 bits (16=2^4) so he is checking if the last 4 bits of each address are divisible by 16.
If this is still very confusing you might want to make sure you understand binary integers before continuing.
Discusses a cache's block
You saved my life
Thank you
I have another question if it is not too much to ask. In real enterprise environment where this is used , how to they build the physical side the network to accomodate this ? I know that a router has to be employed to route traffic across different subnets but is that the case in real time environments. For example , If I have 4 subnets should I have 4 routers ?
What if the Octet Decimal value of the octet that is being worked has a value less than Block Size.
For example, taking your second example , instead of 192.168.18.101 /29 , what will happen if it is 192.168.18.4/29 ? Since the block size 8 does not even fit once in in the 4th octet which is "4" , will it be 0 then ?
Like the network ID : 192.168.18.0 ??
Also what if the 4th octet value matches exactly on one of the 8's multiple , say for example,
192.168.18.64 /29.
In this case , will the network ID be 192.168.18.64 ? Or 192.168.18. 56 ?
( in other words should be less than the octet decimal value or lesser or equal to octet decimal value )
Thank you man.
What if you are dealing /8
Thank You so much, this video clears up a lot for me. Well done sir